The Monty Hall Problem
Author | joem |
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Tags | author:joem rated test |
Created | 2005-09-13 |
Rating |
4 by 11 people.
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Map Data | |
Description | Ok, for those of you who don't know. The monty hall problem involves 3 doors. One of which contains a prize, the other two do not. Firstly you choose one of the doors (top middle bottom in this case). This will cause the contents of one of the other doors to become apparent, thanks to the 3 view holes underneath. You the choose your door. Simple as.
I know this isn't much of a problem, which is why it isn't categorized as a puzzle. I just thought it would be fun to make an N version of the puzzle. Incidentally, 2 times out of 3 you should change your decision. Does anyone know why? |
Comments
Pages: (0)
2005-11-06
Great
I wish I had thought of this. I made one similar to his though. ( http://numa.notdot.net/map/17335 ) The only problem is that you can only really play it once. It would be better if it had something to make it more random.
2005-09-15
Good
Im happy that someone made a N level out of this.
4/5
4/5
2005-09-14
...
Nice quiz level, 5/5
2005-09-13
Great idea...
When I hear the problem, I don't get why it's better to switch. Then after thinking about it for a long time I just barely grasp the reason. Then next time I hear it it's back to square one. =P
2005-09-13
I know it
It's pretty hard to work out, unless you tackle it graphically.
Nice ideas map.
Nice ideas map.
I shall give you 5 out of 5.
2005-09-13
I know why....
When you initally chose, you chose randomly out of three. You're likelihood of picking the correct one initially was 1 in 3. You're likelihood of picking the wrong one initially was 2 in 3.
When they reveal the other wrong door, you are left with your door and one other. One of these doors contains the prize. If you picked correctly initially then you wouldn't want to switch. If you picked incorrectly initially, then you would want to switch. Initially, there was a 2 in 3 chance you picked the wrong one, so if you switch, 2 out of 3 times, you will switch to the correct one (sine the incorrect one was eliminated). There is only a 1 in 3 chance that you picked the correct one initially and thus only a 1 in 3 chance that switching would be bad.
Incidentally, this was never done on Monty Hall's "Let's Make a Deal". It was only assumed that this was being done by the question. In actuality, when you picked a door you were stuck with what you chose. I know. I grew up watching "Let's Make a Deal", (Man, do I feel old.)
Anyway, a minor in Mathematics can do a man a world of good at solving what initally appears as a paradox.
When they reveal the other wrong door, you are left with your door and one other. One of these doors contains the prize. If you picked correctly initially then you wouldn't want to switch. If you picked incorrectly initially, then you would want to switch. Initially, there was a 2 in 3 chance you picked the wrong one, so if you switch, 2 out of 3 times, you will switch to the correct one (sine the incorrect one was eliminated). There is only a 1 in 3 chance that you picked the correct one initially and thus only a 1 in 3 chance that switching would be bad.
Incidentally, this was never done on Monty Hall's "Let's Make a Deal". It was only assumed that this was being done by the question. In actuality, when you picked a door you were stuck with what you chose. I know. I grew up watching "Let's Make a Deal", (Man, do I feel old.)
Anyway, a minor in Mathematics can do a man a world of good at solving what initally appears as a paradox.
Hindi
Pretty neat concept and execution.
Mmm... I suppose it might be possible.